Synthesis, structure and reactivities of the dinuclear μ-η16-arylethynyl ruthenium complexes [Cp(PR3)2Ru(μ-η16-C≢CC6H4Me-p)RuCp*]·Cl (R=Ph, Me; Cp=η5-C5H5, Cp*=η5-C5Me5). The molecular

Hiroyuki Matsuzaka, Hironobu Okimura, Yoshiyuki Sato, Tomohiko Ishii, Masahiro Yamashita, Mitsuru Kondo, Susumu Kitagawa, Moto o. Shiro, Mikio Yamasaki

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8 Citations (Scopus)


Treatment of [Cp(PR3)2Ru(C≢CC6H4Me-p) (1a, R=Ph 1b, R=Me; Cp=η5-C5H5) with [Cp*Ru(μ3·Cl)]4 (Cp*=η5-C5Me5) selectively produced the novel dinuclear μ-η16- arylethynyl complex Cp(PR3)2Ru(μ-η16-C≢CC6H4Me-p)RuCp*] (2·Cl: 2a, R=Ph; 2b, R=Me). Protonation of 2·OTf (OTf=OSO2CF3) by TfOH afforded the corresponding vinylidene complex [Cp(PR3)2Ru(μ-η16-C=CHC 6H4Me-p)RuCp*]·[OTf]2 (3·[OTf]2: 3a, R=Ph; 3b, R=Me), which regenerated 2·OTf upon treatment with LiBHEt3. Reaction of 2a·Cl with I2 and subsequent anion metathesis with AgBF4 produced the iodovinylidene complex [Cp(PPh3)2Ru(μ-η16-C=CI C6H4Me-p)RuCp*]·[BF4]2 (4·[BF4]2), whereas similar treatment of 2b·PF6 yielded the iodo/arylethynyl complex [Cp(I)(PMe3)2Ru(μ-η16-C ≢CC6H4Me-p)RuCp*]·[PF6]2 (5·[PF6]2). Substitution of one of the PPh3 ligands in 2a·OTf proceeded under 1 atm of CO to form [Cp(PPh3)(CO)Ru(μ-η16-C≢CC6H4Me-p)RuCp*]·OTf (6·OTf). The molecular structure of 2a·PF6 was determined by X-ray crystallography.

Original languageEnglish
Pages (from-to)133-139
Number of pages7
JournalJournal of Organometallic Chemistry
Issue number2
Publication statusPublished - 2001 Apr 22
Externally publishedYes


  • Arylethynyl
  • Dinuclear complexes
  • Iodovinylidene
  • Ruthenium
  • Vinylidene
  • X-ray crystal structures

ASJC Scopus subject areas

  • Biochemistry
  • Physical and Theoretical Chemistry
  • Organic Chemistry
  • Inorganic Chemistry
  • Materials Chemistry


Dive into the research topics of 'Synthesis, structure and reactivities of the dinuclear μ-η<sup>1</sup>:η<sup>6</sup>-arylethynyl ruthenium complexes [Cp(PR<sub>3</sub>)<sub>2</sub>Ru(μ-η<sup>1</sup>:η<sup>6</sup>-C≢CC<sub>6</sub>H<sub>4</sub>Me-p)RuCp*]·Cl (R=Ph, Me; Cp=η<sup>5</sup>-C<sub>5</sub>H<sub>5</sub>, Cp*=η<sup>5</sup>-C<sub>5</sub>Me<sub>5</sub>). The molecular'. Together they form a unique fingerprint.

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